Conditional display of fields using PHP code – if empty don't display

Hi.

I have a question similar to <a href="http://wp-types.com/forums/topic/conditionally-display-html-labels-for-fields-no-display-when-empty/">this one</a> but I am implementing the fields using php code.

This is what I have:

<dt class="productLabel"><?php echo __( 'Appellation:', 'formulawino' ); ?></dt><dd class="productDescription"><?php echo(types_render_field('fw_product_wine_appellation', array('class'=>''))); ?></dd>

and I would like to not to display the label if the field is empty. Would you be able to help me with this?

Thank you.